The area of the region bounded by `x^2+y^2-2x-3=0` and `y=|x|+1` `pi/2-1s qdotu n i t s` (b) `2pis qdotu n i t s` `4pis qdotu n i t s` (d) `pi/2s qdotu n i t s`

The area of the region bounded by x=0,y=0,x=2,y=2,ylt=e^x a n dygeq1nx is 6-41n2s qdotu n i t s (b) 41n2-2s qdotu n i t s 21n2-4s qdotu n i t s (d) 6-21n2s qdotu n i t s

The area of the region enclosed between the curves x=y^2-1a n dx=|y|sqrt(1-y^2) is 1s qdotu n i t s (b) 4/3s qdotu n i t s 2/3s qdotu n i t s (d) 2s qdotu n i t s

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

The area bounded by the curve a^2y=x^2(x+a) and the x-axis is (a^2)/3s qdotu n i t s (b) (a^2)/4s qdotu n i t s (3a^2)/4s qdotu n i t s (d) (a^2)/(12)s qdotu n i t s

The area bounded by the curve y^2=8x\ a n d\ x^2=8y is (16)/3s qdotu n i t s b. 3/(16)s qdotu n i t s c. (14)/3s qdotu n i t s d. 3/(14)s qdotu n i t s

Let f(x)=m in i mu m(x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is 7/3s qdotu n i t s 1/6s qdotu n i t s (11)/6s qdotu n i t s (d) 7/6s qdotu n i t s

If f(x)=sinx ,AAx in [0,pi/2],f(x)+f(pi-x)=2,AAx in (pi/2,pi)a n df(x)=f(2pi-x),AAx in (pi,2pi), then the area enclosed by y=f(x) and the x-axis is pis qdotu n i t s (b) 2pis qdotu n i t s 2s qdotu n i t s (d) 4s qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

The minimum area of circle which touches the parabolas y=x^2+1 and y^2=x-1 is (9pi)/(16)s qdotu n i t (b) (9pi)/(32)s qdotu n i t (9pi)/8s qdotu n i t (d) (9pi)/4s qdotu n i t

What is the area of the shaded region? (FIGURE) 32-4 pi s qdotu n i t s (b) 32-8 pi s qdotu n i t s (c) 16-4 pi s qdotu n i t s (d) 16-8 pi s qdotu n i t s