The value of m, for wnich the line y=mx ...

The value of m, for wnich the line `y=mx + 25sqrt3/3` is a normal to the conic ` x^2 /16 - y^2 / 9 =1` , IS

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Find the value of m, for which the line y=mx + 25sqrt3/3 is a normal to the conic x^2 /16 - y^2 / 9 =1 .

Find the value of m, for which the line y=mx + 25sqrt3/3 is a normal to the conic x^2 /16 - y^2 / 9 =1 .

The value for m for which the line y=m x+(25)/(sqrt(3)) is a normal to the conic (x^(2))/(16)-(y^(2))/(9)=1 is

the value of lambda for which the line 2x-8/3lambday=-3 is a normal to the conic x^2+y^2/4=1 is:

the value of lambda for which the line 2x-8/3lambday=-3 is a normal to the conic x^2+y^2/4=1 is:

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