If `x+1/ x=2` then the solution of `2cos theta=x` is

Given 12sin theta+5cos theta=2x^(2)-8x+21 and theta and x are the solutions of the above then theta x is

if 2(2 sin theta -1)x^(2)+8x+4(1+sin theta)geforall x in R then find the general solution of theta

If 2cos theta=x+1/x then 2cos^2 theta=

If 2 cos theta=x+(1)/(x) and 2 cos phi=y+(1)/(y) then the value of cos (theta+phi) will be

theta_1 and theta_2 are the inclination of lines L_1a n dL_2 with the x-axis. If L_1a n dL_2 pass through P(x_1,y_1) , then the equation of one of the angle bisector of these lines is (a) (x-x_1)/(cos((theta_1-theta_2)/2))=(y-y_1)/(sin((theta_1-theta_2)/2)) (b) (x-x_1)/(-sin((theta_1-theta_2)/2))=(y-y_1)/(cos((theta_1-theta_2)/2)) (c) (x-x_1)/(sin((theta_1-theta_2)/2))=(y-y_1)/(cos((theta_1-theta_2)/2)) (d) (x-x_1)/(-sin((theta_1-theta_2)/2))=(y-y_1)/(cos((theta_1-theta_2)/2))

theta_1 and theta_2 are the inclination of lines L_1a n dL_2 with the x-axis. If L_1a n dL_2 pass through P(x_1,y_1) , then the equation of one of the angle bisector of these lines is (a) (x-x_1)/(cos((theta_1-theta_2)/2))=(y-y_1)/(sin((theta_1-theta_2)/2)) (b)(x-x_1)/(-sin((theta_1-theta_2)/2))=(y-y_1)/(cos((theta_1-theta_2)/2)) (c)(x-x_1)/(sin((theta_1-theta_2)/2))=(y-y_1)/(cos((theta_1-theta_2)/2)) (d)(x-x_1)/(-sin((theta_1-theta_2)/2))=(y-y_1)/(cos((theta_1-theta_2)/2))