Why does only a slow neutron (.03 eV ene...

Why does only a slow neutron (.03 eV energy) cause the fission in the uranium nucleus and not the fast one ?

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Slow neutron stays in the nucleus for required optimum time and distrubs the configuration of nucleus.

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Find the number of fissions required to produce a power of 2,000 W, if 200 MeV of energy is produced in the fission of single uranium nucleus.

On an average , the number of neutrons and the energy of a neutron released per fission of a uranium atom are respectively

A slow neutron strikes a nucleus of ._(92)^(235)U splitting it into lighter nuclei of ._(56)^(141)Ba and ._(36)^(92)Kr along with three neutrons. The energy released in this reaction is ( The masses of uranium, barium and krypton of this reaction are 235.043933,140.917700 and 91.895400 u respectively. The mass of a neutron is 1.008665 u

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In a nuclear reactor, the neutrons produced in fission reaction have high kinetic energy of the order of few MeV. Whereas the U^(235) nucleus fissions only iwht a slow neutron. In a reactor heavy water (D_(2)O) is used to slow down the neutrons. A neutron hiting a deuterium nucleus slows down quickly. Calculate now many head on, elastic collisions must a neutron have with deuterium nuclei to reduce does not lose energy by any other way apart from collisions with deuterium. [Take "log"_(10)2=0.301 and "log"_(10)3=0.477 ]

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