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Write the relation for distance of close...

Write the relation for distance of closest approach.

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To derive the relation for the distance of closest approach between an alpha particle and a target nucleus, we can follow these steps: ### Step 1: Understand the Concept of Closest Approach The distance of closest approach refers to the minimum distance between two charged particles, in this case, an alpha particle and a nucleus. At this point, the kinetic energy of the alpha particle is completely converted into potential energy due to the electrostatic interaction between the two charges. ### Step 2: Write the Expression for Kinetic Energy The kinetic energy (KE) of the alpha particle can be expressed as: \[ ...
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Write the expression for distance of closest approach for a alpha -particle.

Write the relation for (i) the distance of closest approach and (ii) impact parameter.

Knowledge Check

  • In mu-particle scattering experiment, the expression of distance of closest approach ( r_0 )is (symbols have their usual meanings)

    A
    `1/(4πepsilon_0) × (Ze^2)/E`
    B
    `1/(4πepsilon_0) × (2Ze^2)/E`
    C
    `1/(4πepsilon_0) × (Z^2e^2)`
    D
    `1/(4πepsilon_0)×(Z^2e^4)/E`

  • If an alpha -particle is incident directly towards a nucleus then it will stop when the distance between them is the distance of closest approach. Which of these is correct?

    A
    Its kinetic energy is converted into released radiation
    B
    When its kinetic energy becomes zero then it converts into electrostatic potential energy
    C
    At distance of closest approach the potential energy of the `alpha`-particle becomes zero
    D
    A `beta`-particle will show the same behaviour as an `alpha`-particle

  • The distance between the a-particle and target nucleus in an alpha -scattering experiment is equal to distance of closest approach, when the scattering angle is

    A
    `pi //2`
    B
    `pi`
    C
    `pi //4`
    D
    `pi //3`

    • Similar Questions

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    Define the distance of closest approach.

    An alpha -particle moving with initial kinetic energy 'K' towards a nucleus of atomic number Z approaches a distance ' r_(0) ' at which it reverses its direction. Obtain the expression for the distance of closest approach ' r_(0) ' in terms of kinetic energy of a particle.

    An alpha - particle moving with initial kinetic energy K towards a nucleus of atomic number z approaches a distance 'd' at which it reverse its direction. Obtain the expression for the distance of closest approach 'd' in terms of the kinetic energy of alpha - particle K.

    What happens to the kinetic energy of the particle at the distance of closest approach?

    In a Geiger Marsden experiment, calculate the distance of closest approach to the nucleus of Z 80, when and particle of 8 MeV energy impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the O-particle is doubled ?

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