The work function of the following metal is given Na = 2.75 eV, K=2.3 eV, Mo= 4.14 eV, Ni =5.15 eV which of these metal will not give a photoelectric emission for radiation of wave length `3300 A^@` from a laser source placed at 1m away from the metal . What happens if the laser is brought nearer and placed 50 cm away.

Explanation

To determine which of the metals will not give photoelectric emission for radiation of wavelength \(3300 \, \text{Å}\), we need to follow these steps:

### Step 1: Calculate the energy of the incident radiation
The energy of the incident radiation can be calculated using the formula:

\[ E = \frac{hc}{\lambda} \]
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