Light of intensity I and frequency v is incident on a photossensitive surface and causes photoelectric emission. Justify with the help of graph, the effect on photoelectric current when
the anode potential is increased
In each case, all other factors remain the same.

Light of intensity I and frequency v is incident on a photossensitive surface and causes photoelectric emission. Justify with the help of graph, the effect on photoelectric current when the frequency of incident radiation is increased all other factors remain the same.

Light of intensity I and frequency v is incident on a photosenstive surface and causes photoelectric emission. What will be the effect on anode current when (i) the intensity of light is gradually increased, (ii) the frequency of incident radiation is increased and (iii) the anode potential is increased? In each case, all other factors remains the same. Explain, giving justification in each case.

Plot a graph showing the variation of photoelectric current with anode potential for two light beam of same wavelength but different intensity.

In photoelectric effect , the curve between photoelectric current and anode potential V (for different frequencies ) is shown in figure , then

Light of a particular frequency v is incident on a metal surface. When the intensity of incident radiation is increased, the photoelectric current

Light of frequency .25 v_0 is incident on a metal surface of threshold frequency 2 v_0 . If its frequency is halved and intensity is made three times then find the new value of photoelectric current.

When light of sufficiently high frequency is incident on a metallic surface, electrons are emitted from the metallic surface. This phenomenon is called photoelectric emission. Kinetic energy of the emitted photoelectrons depends on the wavelength of incident light and is independent of the intensity of light. Number of emitted photoelectrons depends on intensity. (hv-phi) is the maximum kinetic energy of emitted photoelectron (where phi is the work function of metallic surface). Reverse effect of photo emission produces X-ray. X-ray is not deflected by electric and magnetic fields. Wavelength of a continuous X-ray depends on potential difference across the tuve. Wavelength of charasteristic X-ray depends on the atomic number. Q. If potential difference across the tube is increased then