Binding energy of `""_2He^4 and ""_3Li^7` nuclei are 27.37 MeV and 39.4 MeV respectively. Which of the two nuclei is more stable? Why?

Explanation

To determine which of the two nuclei, helium-4 (He-4) or lithium-7 (Li-7), is more stable based on their binding energies, we can follow these steps:

### Step 1: Identify the Binding Energies
The binding energies given are:
- Binding energy of He-4 = 27.37 MeV
- Binding energy of Li-7 = 39.4 MeV

### Step 2: Calculate the Number of Nucleons
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