Find the binding energy and binding energy per nucleon of nucleus `""_(83)Bi^(209)`. Given : mass of proton = 1.0078254 u. mass of neutron = 1.008665 u.
Mass of `""_(83)Bi^(209)= 208.980388u`

Explanation

To find the binding energy and binding energy per nucleon of the nucleus \( _{83}^{209}\text{Bi} \), we will follow these steps:

### Step 1: Identify the values
- Atomic number \( Z = 83 \) (number of protons)
- Mass number \( A = 209 \) (total number of nucleons)
- Number of neutrons \( N = A - Z = 209 - 83 = 126 \)

### Step 2: Calculate the mass of the nucleus
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