In car lift compressed air exerts a force `F_1` on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the car to be lifted is 1350 kg, what is `F_1 ?` What is the pressure necessary to ac complish this task ?

Explanation

`(F_(1))/(A_(1))=(F_(2))/(A_(2))`
`F_(1)=F_(2)(A_(1))/(A_(2)) = F_(2)((pir_(1)^(2))/(pir_(2)^(2)))`
`F_(1)= 1350xx9.8((5xx10^(-2))/(15xx10^(2)))^(2)`
=1470 N.