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Time period of a particle in S.H.M. Depe...

Time period of a particle in S.H.M. Depends on the force constant K and mass m of the particle `T=2pisqrtm//k`. A simple pendulum for small angular displacement executes S.H.M. approximately. Why then is the time periodof a pendulum independent of the mass of the pendulum ?

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Restoring force in case of simple pendulum is given by `F= (mg)/l y Rightarrow K =(mg)/l` So force constant itself proportional to` m` as the value of `k` is substituted in the formula, `m` is cancelled out.
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Answer the following questions: (a) Time period of particle is S.H.M. depends on the force constant k and mass m of the particle : T=2pisqrt(m//k). A simple pendulum executes S.H.M. approximately. Why then is the time-period of a pendulum independent of the mass of the pendulum? (b) The motino of simple pendulum is approximatley simple harmonic for small angles of oscillation. For large angle of oscillation, a more involved analysis (beyond the scope of this book) shows that T is greater that 2pisqrt(l//g) . Think of a quanlitative argument to appreciate this result. (c) A man with a wrist watch on his hand falls from the top of tower. Does the watch give correct time during the free fall? (d) What is teh frequency of oscillation of a simple pendulum mounted iin a cabin that is freely falling under gravity?

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CBSE COMPLEMENTARY MATERIAL-MECHANICAL WAVES-TWO MARK QUESTIONS
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