At what temperature will the speed of sound be double its value at 273K?

Explanation

Say `v^(1)` in the velocity of sound at `T_(1)=273^(@)K` and `v^(2)=2v_(1)`at temperature `T_(2)`
Now `v_(2)/v_(1)= sqrt((T_(2))/T_(1)), therefore 2v_(1)//v_(1) = sqrt(T/273)
or T_(2)=4** 273=1092^(@)K`.