Divide:
(i) `8x^(2) y^(2)` by - 2xy (ii) `-15 x^(3) yz^(3)` by `-5xyz^(2)`

Answer

Let's solve the given problems step by step.

### (i) Divide `8x^(2) y^(2)` by `-2xy`

1. **Write the expression**: We need to divide \( 8x^2y^2 \) by \( -2xy \).
\[ \frac{8x^2y^2}{-2xy} \]

2. **Divide the coefficients**: Divide the numerical coefficients \( 8 \) and \( -2 \).
\[ \frac{8}{-2} = -4 \]

3. **Divide the variables**: For the variables, use the property of exponents \( \frac{a^m}{a^n} = a^{m-n} \).
- For \( x \): \( \frac{x^2}{x^1} = x^{2-1} = x^1 = x \)
- For \( y \): \( \frac{y^2}{y^1} = y^{2-1} = y^1 = y \)

4. **Combine the results**: Now combine the results from the coefficients and the variables.
\[ -4xy \]

So, the result of dividing \( 8x^2y^2 \) by \( -2xy \) is:
\[ \boxed{-4xy} \]

### (ii) Divide `-15 x^(3) yz^(3)` by `-5xyz^(2)`

1. **Write the expression**: We need to divide \( -15x^3yz^3 \) by \( -5xyz^2 \).
\[ \frac{-15x^3yz^3}{-5xyz^2} \]

2. **Divide the coefficients**: Divide the numerical coefficients \( -15 \) and \( -5 \).
\[ \frac{-15}{-5} = 3 \]

3. **Divide the variables**: Again, use the property of exponents.
- For \( x \): \( \frac{x^3}{x^1} = x^{3-1} = x^2 \)
- For \( y \): \( \frac{y^1}{y^1} = y^{1-1} = y^0 = 1 \) (which can be ignored)
- For \( z \): \( \frac{z^3}{z^2} = z^{3-2} = z^1 = z \)

4. **Combine the results**: Now combine the results from the coefficients and the variables.
\[ 3x^2z \]

So, the result of dividing \( -15x^3yz^3 \) by \( -5xyz^2 \) is:
\[ \boxed{3x^2z} \]