Add:
`6p + 4q - r + 3, 3r - 5p - 6, 11q - 7p + 2r - 1 and 2q - 3r + 4 `

Answer

To solve the problem of adding the algebraic expressions \(6p + 4q - r + 3\), \(3r - 5p - 6\), \(11q - 7p + 2r - 1\), and \(2q - 3r + 4\), we will follow these steps:

### Step 1: Write down all the expressions
We have the following expressions to add:
1. \(6p + 4q - r + 3\)
2. \(3r - 5p - 6\)
3. \(11q - 7p + 2r - 1\)
4. \(2q - 3r + 4\)

### Step 2: Combine like terms
We will group the like terms (terms with the same variable) from all four expressions.

- For \(p\) terms: \(6p - 5p - 7p\)
- For \(q\) terms: \(4q + 11q + 2q\)
- For \(r\) terms: \(-r + 3r + 2r - 3r\)
- For constant terms: \(3 - 6 - 1 + 4\)

### Step 3: Calculate each group
Now we will calculate each group of like terms:

1. **For \(p\) terms:**
\[ 6p - 5p - 7p = (6 - 5 - 7)p = -6p \]

2. **For \(q\) terms:**
\[ 4q + 11q + 2q = (4 + 11 + 2)q = 17q \]

3. **For \(r\) terms:**
\[ -r + 3r + 2r - 3r = (-1 + 3 + 2 - 3)r = 1r = r \]

4. **For constant terms:**
\[ 3 - 6 - 1 + 4 = (3 - 6 - 1 + 4) = 0 \]

### Step 4: Combine the results
Now we combine all the results from the calculations:

\[ -6p + 17q + r + 0 \]

### Final Result
Thus, the sum of the given algebraic expressions is:
\[ -6p + 17q + r \]