Subtract :
`2a - 5b + 2c - 9" from "3a - 4b - c + 6`

Answer

To solve the problem of subtracting \(2a - 5b + 2c - 9\) from \(3a - 4b - c + 6\), we will follow these steps:

### Step 1: Write the expression for subtraction
We need to subtract \(2a - 5b + 2c - 9\) from \(3a - 4b - c + 6\). This can be written as:
\[ (3a - 4b - c + 6) - (2a - 5b + 2c - 9) \]

### Step 2: Distribute the negative sign
When we subtract the second expression, we need to change the signs of each term in that expression:
\[ 3a - 4b - c + 6 - 2a + 5b - 2c + 9 \]

### Step 3: Combine like terms
Now, we will combine the like terms:
- Combine the \(a\) terms: \(3a - 2a = 1a\) or simply \(a\)
- Combine the \(b\) terms: \(-4b + 5b = 1b\) or simply \(b\)
- Combine the \(c\) terms: \(-c - 2c = -3c\)
- Combine the constant terms: \(6 + 9 = 15\)

Putting it all together, we have:
\[ a + b - 3c + 15 \]

### Final Answer
Thus, the result of the subtraction is:
\[ a + b - 3c + 15 \]

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