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Factorise: 2n^2 + 3n...

Factorise: `2n^2 + 3n`

A

`n(2n^2+3)`

B

`n^2(2n+3)`

C

`n(2n+3)`

D

`n(2n-3)`

Text Solution

AI Generated Solution

The correct Answer is:
To factorise the expression \(2n^2 + 3n\), we can follow these steps: ### Step 1: Identify the common factor Look for the common factor in both terms of the expression \(2n^2\) and \(3n\). **Common factor:** Both terms have \(n\) as a common factor. ### Step 2: Factor out the common factor Now, we can factor out \(n\) from the expression: \[ 2n^2 + 3n = n(2n + 3) \] ### Step 3: Write the final factorised form The expression is now fully factorised. The final answer is: \[ n(2n + 3) \] ### Summary of the factorisation: The factorised form of \(2n^2 + 3n\) is \(n(2n + 3)\). ---
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