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Factorles: 12a ^(2) b- 9ab^(2) + 6ab...

Factorles:
` 12a ^(2) b- 9ab^(2) + 6ab`

A

`3 ab (4a + 3b +2)`

B

`3 ab (4a - 3b -2)`

C

`3 ab (4a - 3b +2)`

D

`3 ab (4a + 3b -2)`

Text Solution

AI Generated Solution

The correct Answer is:
To factor the expression \( 12a^2b - 9ab^2 + 6ab \), we will follow these steps: ### Step 1: Identify the common factors in each term The given expression is \( 12a^2b - 9ab^2 + 6ab \). We will look for the greatest common factor (GCF) of the coefficients and the variables in each term. - The coefficients are 12, -9, and 6. The GCF of these numbers is 3. - The variable part includes \( a^2, ab^2, \) and \( ab \). The common variable factor is \( ab \) (the lowest power of \( a \) is \( a^1 \) and the lowest power of \( b \) is \( b^1 \)). Thus, the GCF of the entire expression is \( 3ab \). ### Step 2: Factor out the GCF Now we will factor out \( 3ab \) from each term in the expression: \[ 12a^2b - 9ab^2 + 6ab = 3ab(4a) - 3ab(3b) + 3ab(2) \] ### Step 3: Write the expression in factored form Now, we can write the expression as: \[ 3ab(4a - 3b + 2) \] ### Final Answer The factored form of the expression \( 12a^2b - 9ab^2 + 6ab \) is: \[ 3ab(4a - 3b + 2) \] ---
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