Home
Class 8
MATHS
Factorise: ar + br + at + bt...

Factorise:
`ar + br + at + bt`

Text Solution

AI Generated Solution

The correct Answer is:
To factorise the expression \( ar + br + at + bt \), we can follow these steps: 1. **Group the terms**: We can group the terms in pairs. \[ (ar + br) + (at + bt) \] 2. **Factor out the common factors**: In each group, we can factor out the common factor. - From the first group \( ar + br \), the common factor is \( r \). - From the second group \( at + bt \), the common factor is \( t \). \[ r(a + b) + t(a + b) \] 3. **Factor out the common binomial**: Now, we notice that \( (a + b) \) is common in both terms. \[ (a + b)(r + t) \] Thus, the factorised form of \( ar + br + at + bt \) is: \[ (a + b)(r + t) \]
Promotional Banner

Topper's Solved these Questions

  • FACTORISATION

    RS AGGARWAL|Exercise EXERCISE 7B|28 Videos
  • FACTORISATION

    RS AGGARWAL|Exercise EXERCISE 7C|19 Videos
  • FACTORISATION

    RS AGGARWAL|Exercise SOLVED EXAMPLES|22 Videos
  • EXPONENTS

    RS AGGARWAL|Exercise TEST PAPER-2|18 Videos
  • INTRODUCTION TO COORDINATE GEOMETRY

    RS AGGARWAL|Exercise EXERCISE B (OBJECTIVE QUESTIONS)|7 Videos

Similar Questions

Explore conceptually related problems

Bt toxins are

Factorisation - How to Factorise?

Bt toxin is a

Bt-toxin is a

Draw Lewis symbols for the following elements : B, Ge, Si, Ar, Ca, K, As, Br.

What do you mean by Bt in Bt-cotton ?

If the medians of a triangle ABC intersect at G, show that ar(triangleAGB)=ar(triangleAGC)=ar(triangleBGC) =(1)/(3)ar(triangleABC) .

In the adjacent figure P is a point inside the parallelogram ABCD. Prove that ar (APD) + ar (PBC) = ar (APB) + ar (PCD)