Home
Class 8
MATHS
Fractorise: 81-49x ^(2)...

Fractorise:
`81-49x ^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To factorize the expression \( 81 - 49x^2 \), we can follow these steps: ### Step 1: Identify the squares We can rewrite \( 81 \) and \( 49x^2 \) as squares: - \( 81 = 9^2 \) - \( 49x^2 = (7x)^2 \) ### Step 2: Recognize the difference of squares The expression \( 81 - 49x^2 \) can now be expressed as: \[ 9^2 - (7x)^2 \] This is in the form of \( a^2 - b^2 \), where \( a = 9 \) and \( b = 7x \). ### Step 3: Apply the difference of squares formula We can use the difference of squares formula: \[ a^2 - b^2 = (a + b)(a - b) \] Substituting \( a \) and \( b \): \[ (9 + 7x)(9 - 7x) \] ### Final Answer Thus, the factorization of \( 81 - 49x^2 \) is: \[ (9 + 7x)(9 - 7x) \] ---
Promotional Banner

Topper's Solved these Questions

  • FACTORISATION

    RS AGGARWAL|Exercise EXERCISE 7C|19 Videos
  • FACTORISATION

    RS AGGARWAL|Exercise EXERCISE 7D|42 Videos
  • FACTORISATION

    RS AGGARWAL|Exercise EXERCISE 7A|39 Videos
  • EXPONENTS

    RS AGGARWAL|Exercise TEST PAPER-2|18 Videos
  • INTRODUCTION TO COORDINATE GEOMETRY

    RS AGGARWAL|Exercise EXERCISE B (OBJECTIVE QUESTIONS)|7 Videos

Similar Questions

Explore conceptually related problems

Fractorise: x ^(3)-3x ^(2) + x-3

Fractorise: 12x ^(2) - 27

Fractorise: 100-(x-5)^(2)

Fractorise: 1- (b-c)^(2)

Fractorise: 12x +15

Fractorise: 14m -21

Fractorise the 4x ^(2) - 20 x + 25

Fractorise: 4x ^(2) -9y^(2)

Fractorise: ab (x ^(2) + y^(2) ) + xy (a^(2) + b ^(2)).

Fractorise: x ^(2) -y ^(2) - 2y -1