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Factorise: x ^(2) - 10x + 24...

Factorise:
`x ^(2) - 10x + 24`

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To factorise the expression \( x^2 - 10x + 24 \), we will follow these steps: ### Step 1: Identify the coefficients The given quadratic expression is \( x^2 - 10x + 24 \). - Coefficient of \( x^2 \) (let's call it \( a \)) = 1 - Coefficient of \( x \) (let's call it \( b \)) = -10 - Constant term (let's call it \( c \)) = 24 ### Step 2: Multiply \( a \) and \( c \) We will multiply the coefficient of \( x^2 \) (which is 1) with the constant term (which is 24): \[ a \cdot c = 1 \cdot 24 = 24 \] ### Step 3: Find two numbers that multiply to \( ac \) and add to \( b \) We need to find two numbers that multiply to 24 and add up to -10. The numbers that satisfy these conditions are -6 and -4 because: \[ -6 \cdot -4 = 24 \quad \text{and} \quad -6 + -4 = -10 \] ### Step 4: Rewrite the middle term Now we can rewrite the expression \( x^2 - 10x + 24 \) by splitting the middle term using the numbers we found: \[ x^2 - 6x - 4x + 24 \] ### Step 5: Group the terms Next, we will group the terms: \[ (x^2 - 6x) + (-4x + 24) \] ### Step 6: Factor out the common terms Now we factor out the common factors from each group: 1. From \( x^2 - 6x \), we can factor out \( x \): \[ x(x - 6) \] 2. From \( -4x + 24 \), we can factor out -4: \[ -4(x - 6) \] ### Step 7: Combine the factors Now we can combine the factored terms: \[ x(x - 6) - 4(x - 6) \] This can be factored further as: \[ (x - 6)(x - 4) \] ### Final Answer Thus, the factorised form of \( x^2 - 10x + 24 \) is: \[ (x - 6)(x - 4) \] ---
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