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x ^(3) - x =?...

`x ^(3) - x =? `

A

`x (x ^(2) -x)`

B

`x (x -x ^(2))`

C

`x (1+x) (1 -x)`

D

`x (x +1) (x -1)`

Text Solution

AI Generated Solution

The correct Answer is:
To factor the expression \( x^3 - x \), we can follow these steps: ### Step 1: Identify the common factor The expression \( x^3 - x \) has a common factor of \( x \). ### Step 2: Factor out the common factor We can factor out \( x \) from the expression: \[ x^3 - x = x(x^2 - 1) \] ### Step 3: Recognize the difference of squares The expression \( x^2 - 1 \) is a difference of squares, which can be factored further. We know that: \[ a^2 - b^2 = (a + b)(a - b) \] In our case, \( a = x \) and \( b = 1 \). ### Step 4: Factor the difference of squares Applying the difference of squares formula, we can factor \( x^2 - 1 \): \[ x^2 - 1 = (x + 1)(x - 1) \] ### Step 5: Combine the factors Now we can combine all the factors together: \[ x^3 - x = x(x^2 - 1) = x(x + 1)(x - 1) \] ### Final Answer Thus, the fully factored form of \( x^3 - x \) is: \[ x(x + 1)(x - 1) \] ---
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