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A bag contains 4 white and 5 blue balls....

A bag contains 4 white and 5 blue balls. They are mixed throughly and one ball is drawn at random. What is the probability of getting (i) a white ball? (ii) a blue ball?

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To solve the problem, we will calculate the probability of drawing a white ball and a blue ball from a bag containing 4 white balls and 5 blue balls. ### Step-by-Step Solution: 1. **Identify the Total Number of Balls:** - The bag contains 4 white balls and 5 blue balls. - Total number of balls = Number of white balls + Number of blue balls \[ \text{Total balls} = 4 + 5 = 9 \] 2. **Calculate the Probability of Drawing a White Ball:** - The number of favorable outcomes for drawing a white ball = 4 (since there are 4 white balls). - The probability of drawing a white ball is given by the formula: \[ P(\text{White}) = \frac{\text{Number of favorable outcomes for white}}{\text{Total outcomes}} = \frac{4}{9} \] 3. **Calculate the Probability of Drawing a Blue Ball:** - The number of favorable outcomes for drawing a blue ball = 5 (since there are 5 blue balls). - The probability of drawing a blue ball is given by the formula: \[ P(\text{Blue}) = \frac{\text{Number of favorable outcomes for blue}}{\text{Total outcomes}} = \frac{5}{9} \] ### Final Answers: - (i) The probability of getting a white ball is \(\frac{4}{9}\). - (ii) The probability of getting a blue ball is \(\frac{5}{9}\).
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