It is known that a box of 100 electric bulbs contains 8 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective? (ii) non -defective?

Answer

To solve the problem, we need to find the probability of drawing a defective bulb and the probability of drawing a non-defective bulb from a box containing 100 electric bulbs, of which 8 are defective.

### Step-by-Step Solution:

1. **Identify the total number of bulbs:**
- The total number of bulbs in the box is 100.

2. **Identify the number of defective bulbs:**
- The number of defective bulbs is given as 8.

3. **Calculate the number of non-defective bulbs:**
- Non-defective bulbs = Total bulbs - Defective bulbs
- Non-defective bulbs = 100 - 8 = 92

4. **Calculate the probability of drawing a defective bulb:**
- Probability (Defective) = Number of defective bulbs / Total number of bulbs
- Probability (Defective) = 8 / 100
- Simplifying this fraction:
- Divide both the numerator and the denominator by 4:
- Probability (Defective) = 2 / 25

5. **Calculate the probability of drawing a non-defective bulb:**
- Probability (Non-defective) = Number of non-defective bulbs / Total number of bulbs
- Probability (Non-defective) = 92 / 100
- Simplifying this fraction:
- Divide both the numerator and the denominator by 4:
- Probability (Non-defective) = 23 / 25

### Final Answers:
(i) The probability that the bulb drawn is defective = 2/25
(ii) The probability that the bulb drawn is non-defective = 23/25

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