Find an integer a such that
(i) `a + 6 = 0 " " (ii) 5 + a = 0 " " (iii) a + (-4) = 0 " " (iv) -8 + a = 0 `

Answer

Let's solve the problem step by step.

### Question:
Find an integer \( a \) such that:
1. \( a + 6 = 0 \)
2. \( 5 + a = 0 \)
3. \( a + (-4) = 0 \)
4. \( -8 + a = 0 \)

### Step-by-Step Solutions:

#### Part (i): \( a + 6 = 0 \)
1. To isolate \( a \), we subtract 6 from both sides of the equation:
\[ a + 6 - 6 = 0 - 6 \]
2. This simplifies to:
\[ a = -6 \]

#### Part (ii): \( 5 + a = 0 \)
1. To isolate \( a \), we subtract 5 from both sides of the equation:
\[ 5 + a - 5 = 0 - 5 \]
2. This simplifies to:
\[ a = -5 \]

#### Part (iii): \( a + (-4) = 0 \)
1. We can rewrite \( a + (-4) \) as \( a - 4 \). To isolate \( a \), we add 4 to both sides:
\[ a - 4 + 4 = 0 + 4 \]
2. This simplifies to:
\[ a = 4 \]

#### Part (iv): \( -8 + a = 0 \)
1. To isolate \( a \), we add 8 to both sides of the equation:
\[ -8 + a + 8 = 0 + 8 \]
2. This simplifies to:
\[ a = 8 \]

### Summary of Solutions:
1. For \( a + 6 = 0 \), \( a = -6 \)
2. For \( 5 + a = 0 \), \( a = -5 \)
3. For \( a + (-4) = 0 \), \( a = 4 \)
4. For \( -8 + a = 0 \), \( a = 8 \)