On a day in Srinagar, the temperature at 6 p.m. was `1^(@) C` but at midnight that day . It dropped to `-4^(@) C`. By how many degrees Celstus did the temperature fall ?

Options

A. `-5^(@) C`
B. `3^(@) C`
C. `-3^(@) C`
D. `5^(@) C`

Answer

To find out by how many degrees Celsius the temperature fell from 6 p.m. to midnight, we can follow these steps:

### Step 1: Identify the initial and final temperatures.
- The temperature at 6 p.m. was \(1^\circ C\).
- The temperature at midnight was \(-4^\circ C\).

### Step 2: Calculate the difference in temperature.
To find out how much the temperature fell, we need to subtract the final temperature from the initial temperature:

\[ \text{Temperature drop} = \text{Initial temperature} - \text{Final temperature} \]

Substituting the values:

\[ \text{Temperature drop} = 1^\circ C - (-4^\circ C) \]

### Step 3: Simplify the expression.
Subtracting a negative number is the same as adding its positive counterpart:

\[ \text{Temperature drop} = 1^\circ C + 4^\circ C \]

### Step 4: Perform the addition.
Now, we can add the two temperatures:

\[ \text{Temperature drop} = 5^\circ C \]

### Conclusion:
The temperature fell by \(5^\circ C\).

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