The displacement of a particle in `SHM` is `x = 3sin (20 pit) +4 cos(20pit)cm`. Its amplitude of oscillation is

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then acceleration of the particle at 0.1 s is

The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then the speed of the particle at 0.1 s will be

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t . The amplitude and maximum velocity of a particle respectively are………….

The equation for the displacement of a particle executing SHM is x = 5sin (2pit)cm Then the velocity at 3cm from the mean position is( in cm//s)

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is