Statement 1: The determinant of a matrix `A=([a_(i j)])_(5xx5)w h e r ea_(i j)+a_(j i)=0` for all `ia n dj` is zero. Statement 2: The determinant of a skew-symmetric matrix of odd order is zero

Statement-1 (Assertion and Statement- 2 (Reason) Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select the correct choice as given below. Statement-1 The determinant fo a matrix A= [a_(ij)] _(nxxn), where a_(ij) + a_(ji) = 0 for all i and j is zero. Statement- 2 The determinant of a skew-symmetric matrix of odd order is zero.

The determinant of a skew symmetric matrix of odd order is 0 1 - 1 None of these

Construct a matrix [a_(ij)]_(2xx2) where a_(ij)=i+2j

Construct a matrix [a_(ij)]_(3xx3) ,where a_(ij)=(i-j)/(i+j).

In square matrix A=(a_(ij)) if i lt j and a_(ij)=0 then A is

If matrix A=[a_(ij)]_(2xx2^(,)) where a_(ij)=1" if "i!=j =0" if "i=j then A^(2) is equal to :

The square matrix A=[a_(ij)" given by "a_(ij)=(i-j)^3 , is a

Consider the matrix A=[{:(0,-h,-g),(h,0,-f),(g,f, 0):}] STATEMENT-1 : Det A = 0 STATEMENT-2 :The value of the determinant of a skew symmetric matrix of odd order is always zero.

If matrix A=[a_(ij)]_(3xx2) and a_(ij)=(3i-2j)^(2) , then find matrix A.