Home
Class 12
CHEMISTRY
for a given reaction at temeperature T, ...

for a given reaction at temeperature T, the velocity constant k, is expressed as :
`k=ae^(-27000K'//T)` (K' = Boltzmann constant)
Given , `R=2 cal K^(-1) "mol"^(-1)`. Calculate the value of energy of activation. Comment on the results.

Promotional Banner

Similar Questions

Explore conceptually related problems

Boltzmann constant ( k ) is given by

The Boltzmann constant k is given by k = ………..

For a reaction, the rate constant is expressed as k = Ae^(-40000//T) . The energy of the activation is

For a reaction, the rate constant is expressed as k = Ae^(-40000//T) . The energy of the activation is

The quantity (PV)/(k_(B)T) represents the ( k_(B): Boltzmann constant)

The quantity (PV)/(k_(B)T) represents the ( k_(B): Boltzmann constant)

The quantity (PV)/(k_(B)T) represents the ( k_(B): Boltzmann constant)

The ratio of rate constants of a reaction at 300K and 291K is 2. Calculate the energy of activation. ("Given "R = "8.314JK"^(-1)" mol"^(-1)) .

The slope of the line in the graph of log k (k = rate constant) versus 1/T is - 5841. Calculate the activation energy of the reaction.