A sphere is placed rotating with its centre initially at rest in a corner as shown in Figs.(a) and (b). Coefficient of friction between all surfaces and the sphere is `1//3`. Find the ratio of the friction forces `f_(a)//f_(b)` by ground in situations (a) and (b).

A sphere is placed rotating with its centre initially at rest in a corner as shown in figure (a) and (b) . Coefficient of friction between all surfaces and the sphere is (1)/(3) . Find the ratio of the frictional force (f_(a))/(f_(b)) by ground in situations (a) and (b) . .

A sphere is rotating between two rough inclined walls as shown in figure. Coefficient of friction between each wall and the sphere is 1//3 . If f_(1) and f_(2) be the frictional forces at P and Q. Then (f_(1))/(f_(2)) is

A sphere is rotating between two rough inclined walls as shoen in fiogure. Cofficent of friction between each wall and the sphere is (1)/(3) . If f_(1) and f_(2) be the ffriction forces at PO and Q. Then (f_(1))/(f_(2)) is

All surfaces as shown in the figure are rough. Draw the friction force on A & B

If the coefficient of friction between all surface figure is 0.4 then find the minimum force F to have equilibrium of the system.

If the coefficient of friction between all surface figure is 0.4 then find the minimum force F to have equilibrium of the system.

In the show arrangement mass of A=1 kg, mass of B= 2kg. Coefficient of friction between A and B =0.2 There is no friction between B and ground. The frictional force exerted by A on B equals.

In the show arrangement mass of A=1 kg, mass of B= 2kg. Coefficient of friction between A and B =0.2 There is no friction between B and ground. The frictional force exerted by A on B equals.