`(-A)^(-1)` is always equal to (where `A` is nth-order square matrix) `(-A)^(-1)` b. `-A^(-1)` c. `(-1)^nA^(-1)` d. none of these

If A is an orthogonal matrix then A^(-1) equals A^(T) b.A c.A^(2) d.none of these

If for the matrix A ,\ A^3=I , then A^(-1)= A^2 (b) A^3 (c) A (d) none of these

If A^(3)=O, then I+A+A^(2) equals I-A b.(I+A^(1))=^(-1) c.(I-A)^(-1) d.none of these

(A^(3))^(-1)=(A^(-1))^(3) , where A is a square matrix and |A|!=0

If AO, then I+AA2 (where I is the unit matrix of order same as that of square matrix A) is equ (A) I-A(B)(I-A)1dp ) none of these (C)(I+A)

Let A be an nth-order square matrix and B be its adjoint,then |AB+KI_(n)| is (where K is a scalar quantity (|A|+K)^(n-2) b.(|A|+)K^(n) c.(|A|+K)^(n-1) d.none of these

If A is matrix of order 3 such that |A|=5 and B= adj A, then the value of ||A^(-1)|(AB)^(T)| is equal to (where |A| denotes determinant of matrix A. A^(T) denotes transpose of matrix A, A^(-1) denotes inverse of matrix A. adj A denotes adjoint of matrix A)

A square matrix A is invertible iff det (A) is equal to (A) -1 (B) 0 (C) 1 (D) none of these

If A is an invertible matrix then det(A^-1) is equal to (A) 1 (B) 1/|A| (C) |A| (D) none of these

If A is an invertible matrix of order 3, then which of the following is not true (a) |a d j\ A|=|A|^2 (b) (A^(-1))^(-1)=A (c) If B A=C A , then B!=C , where B and C are square matrices of order 3 (d) (A B)^(-1)=B^(-1)A^(-1) , where B=([b_(i j)])_(3xx3) and |B|!=0