There are four six faced dice such that each of two dice bears the numbers 0, 1, 2, 3, 4 and 5 and the other two dice are ordinary dice bearing numbers 1, 2, 3, 4, 5 and 6 if all the four dice are thrown,find the probability that the total of numbers coming up on all the dice is 10, is `(100a+10b+c)/1296`, then