`Off(x)=int_0^x("cos"(sint)+"cos"(cost)dt ,t h e nf(x+pi)i s` (a)`f(x)+f(pi)` (b) `f(x)+2(pi)` (c)`f(x)+f(pi/2)` (d) `f(x)+2f(pi/2)`

Similar Questions

Explore conceptually related problems

If f(x) =int_(0)^(x) sin^(4)t dt , then f(x+2pi) is equal to

If f(x)=int_(0)^(x)(sin^(4)t+cos^(4)t)dt, then f(x+pi) will be equal to

If f(x)=int_0^x e^(cost)/(e^(cost)+e^-(cost))dt , then 2f(pi)= (A) 0 (B) pi (C) -pi (D) none of these

Let f(x)=int_0^x (sin^100t)/(sin^100t+cos^100t)dt then f(2pi)= (A) 2f(pi/2) (B) 4f(pi/2) (C) f(pi/2) (D) none of these

If f(x) = int_(0)^(x)(2cos^(2)3t+3sin^(2)3t)dt , f(x+pi) is equal to :

If f(x)=int_(0)^(cos^(2)x)sec x(sqrt(t))/(1+t^(3))dt then (i) f'(pi)=0( ii) f'(pi)=1 (iii) f'(2 pi)=1( iv )f'(2 pi)=-1

If f(x)=sin x+int_(0)^((pi)/(2))sin x cos tf(t)dt, then int_(0)^((pi)/(2))f(x)dx=

If f(x)=-int_(0)^(x) log (cos t) dt, then the value of f(x)-2f((pi)/(4)+(x)/(2))+2f((pi)/(4)-(x)/(2)) is equal to

f(x)=sinx+int_(-pi//2)^(pi//2)(sinx+tcosx)f(t)dt The range of f(x) is