निम्नलिखित समीकरणों को हल कीजिए :
` cos alpha -cos ( alpha + theta) + cos (alpha+ 2 theta) =0`

tan theta = (sin alpha-cos alpha) / (sin alpha + cos alpha)

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then:

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then:

If tan theta=(sin alpha-cos alpha)/(sin alpha+cos alpha) ,then theta is

Prove that : 2 sin^2 theta + 4 cos (theta + alpha) sin alpha sin theta + cos 2 (alpha + theta) is independent of theta.

If cos 3 theta = alpha cos theta + beta cos ^(3) theta, then (alpha, beta) =

Simplify be reducing to a single term : cos (theta + alpha ) cos ( theta - alpha ) - sin ( theta + alpha ) sin (theta - alpha).

Evaluate int (cos 2 theta - cos 2 alpha )/(sin alpha - sin theta ) d theta

if sin(theta+alpha)=cos(theta+alpha) then tan alpha