In the previous question, find maximum velocity and maximum acceleration.

The ratio of maximum velocity and maximum acceleration of a particle of SHM having amplitude A and angular frequency omega ………..

If alpha and beta denote the maximum velocity and maximum acceleration of a simple harmonic oscillator, then its amplitude of vibration is

For Question , find maximum velocity and maximum acceleration Hint : Maximum velocity = Aomega Maximum acceleration = A omega^(2)

For Question , find maximum velocity and maximum acceleration Hint : Maximum velocity = Aomega Maximum acceleration = A omega^(2) A particle executes SHM on a straight line path. The amplitude of oscillation is 3cm . magnitude of its acceleration is equal to that of its velocity when its displacement from the mean position is 1cm.

A particle is performing simple harmonic motion with amplitude A and angular velocity omega . The ratio of maximum velocity to maximum acceleration is

The amplitude of a simple harmonic oscillation is doubled. How does this affect (i) periodic time (ii) maximum velocity (iii) maximum acceleration and (iv) maximum energy

In the previous question, find the maximum permissible error in resistivity and resistance.

In the previous question, the mean velocity of the rocket reaching the maximum height is :