int_(0)^(2 pi)|sin x|dx

Evaluate : I = int_(0)^(2 pi)(sin x)dx =

Evaluate: int_(0)^(2 pi)[sin x]dx, where [.] denotes the greatest integer function.

Evaluate the following integral: int_0^(2pi)|sin x|dx

Arrange the following according to their values in ascending order A) int_(0)^(pi) |sin x| dx B) int_(0)^(2pi) |sin x | dx C) int_(0)^(3pi) |sin x| dx

int_(0)^(2 pi)(sin x+|sin x|)dx is equal to

Find the following integration :int_(0)^( pi)[2sin x]dx=

The value of int_(0)^(2 pi)[2sin x]dx, where [.] represents the greatest integral functions,is

int_(0)^( pi)xf(sin x)dx=(pi)/(2)int_(0)^( pi)f(sin x)dx

int_(0)^(pi) [2sin x]dx=

int_(0)^(pi) [2sin x]dx=