[" 2.If "a^(2)+b^(2)=1," then "(1+b+ia)/(1+b-ia)=],[[" (a) "1," (b) "2],[" (c) "b+" ia "," (d) "a+ib]]

If a^(2)+b^(2)=1 , prove that (1+b+ia)/(1+b-ia)=b+ia .

If a^(2)+b^(2)=1th en (1+b+ia)/(1+b-ia)=1b.2cb+iad.a+ib

If a^2+b^2=1 , prove that (1+b+ia)/(1+b-ia)= b + ia .

If a,b,c are real numbers and z is a complex number such that,a^(2)+b^(2)+c^(2)=1 and b+ic=(1+a)z then (1+iz)/(1-iz) equals.(a) (b-ic)/(1-ia) (b) (a+ib)/(1+c) (c) (1-c)/(a-ib)( d) (1+a)/(b+ic)

If A,B and C are angles of a triangle ABC then the value of |[4e^(2iA), e^(-iC), e^(-iB)] , [e^(-iC), 4e^(2iB), e^(-iA)] , [e^(-iB), e^(-iA), 4e^(2iC)]| is

If z=(a+ib)^(5)+(b+ia)^(5) then prove that Re(z)=Im(z), where a,b in R.

If sqrt(x+iy)=+-(a+ib) ,then sqrt(-x-iy) is equal to a) +-(b+ia) b) +-(a-ib) c) (ai+b) d) +-(b-ia)

If A+B+C=pi and e^(itheta)=costheta+isintheta and z=|[e^(2iA), e^(-iC), e^(-iB)] , [e^(-iC), e^(2iB), e^(-iA)], [e^(-iB), e^(-iA), e^(2iC)]| , then