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The sequence a1,a2,a3,a4..... satisfies ...

The sequence `a_1,a_2,a_3,a_4`..... satisfies `a_1 =1, a_2 =2 and a_(n+2) = 2/a_(n+1) + a_n, n=1,2,3`.... If `2^(lambda) a_(2012) = (2011!)/(1005!)^2` then `lambda` is equal to

A

`.^(2010)C_(1005)`

B

`.^(2011)C_(1006)`

C

`.^(2011)C_(1005)`

D

`.^(2012)C_(1006)`

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