Home
Class 11
CHEMISTRY
What is the equilibrium constantK(p) " a...

What is the equilibrium constant`K_(p) " and " K_(c)` for the reaction`PCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g)` if the pressure is `1.0` atm in `8.0L` container at equilibrium.

Text Solution

Verified by Experts

The correct Answer is:
`K_(c) = 0.04 K_(p) = 1.77`
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    CBSE COMPLEMENTARY MATERIAL|Exercise HOTS QUESTIONS|10 Videos

  • EQUILIBRIUM

    CBSE COMPLEMENTARY MATERIAL|Exercise UNIT TEST|6 Videos

  • EQUILIBRIUM

    CBSE COMPLEMENTARY MATERIAL|Exercise 2- MARK QUESTIONS|10 Videos

  • ENVIRONMENTAL CHEMISTRY

    CBSE COMPLEMENTARY MATERIAL|Exercise UNIT TEST|9 Videos

  • HYDROCARBONS

    CBSE COMPLEMENTARY MATERIAL|Exercise UNIT TEST|16 Videos

Similar Questions

Explore conceptually related problems

For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temeprature is favoured by

For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl__(2)(g) The forward reaction at constant temperature is favoured by

The equilibrium constant (K_(p)) for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) is 16 . If the volume of the container is reduced to half of its original volume, the value of K_(p) for the reaction at the same temperature will be:

At a given temperature the equilibrium constant for the reaction PCl_(5) (g) Leftrightarrow PCl_(3)(g)+Cl_(2)(g) is 2.4 xx 10^(-3) . At the same temperature the equilibrium constant for the reaction PCl_(3) (g)+Cl_(2)(g) Leftrightarrow PCl_(5) (g)

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is