When `MnO_4–` reacts with `H_2O_2` in basic medium then following species are involved, except

Options

A. `MnO_(2)`
B. `O_(2)`
C. `OH^(-)`
D. `Mn^(2+)`

Answer

To solve the problem of identifying which species is not involved when `MnO4–` reacts with `H2O2` in a basic medium, we can follow these steps:

### Step 1: Write the balanced chemical equation for the reaction.
The reaction of `MnO4–` with `H2O2` in a basic medium can be represented as:
\[ 3 H2O2 + 2 MnO4– + 2 H+ \rightarrow 3 O2 + 2 MnO2 + 4 H2O \]

### Step 2: Adjust for basic conditions.
Since the reaction occurs in a basic medium, we need to add hydroxide ions (OH–) to both sides of the equation to neutralize the hydrogen ions (H+):
\[ 3 H2O2 + 2 MnO4– + 2 H+ + 2 OH– \rightarrow 3 O2 + 2 MnO2 + 4 H2O + 2 OH– \]

### Step 3: Simplify the equation.
Combine the hydrogen ions and hydroxide ions on the left side:
\[ 3 H2O2 + 2 MnO4– + 2 H2O \rightarrow 3 O2 + 2 MnO2 + 4 H2O \]

### Step 4: Identify the species involved.
From the balanced equation, we see that the species involved in the reaction are:
- `MnO4–`
- `H2O2`
- `O2`
- `MnO2`
- `H2O`

### Step 5: Determine which species is not involved.
Now, we need to check the options provided in the question to see which species is not present in the balanced equation. The species that is not involved in this reaction is `Mn^2+`, as it does not appear in the final balanced equation.

### Final Answer:
The species that is not involved when `MnO4–` reacts with `H2O2` in a basic medium is `Mn^2+`.

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