What happens when `Al_4C_3` reacts with `D_2O? `

Answer

To determine what happens when \( \text{Al}_4\text{C}_3 \) (Aluminum Carbide) reacts with \( \text{D}_2\text{O} \) (Heavy Water), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Aluminum Carbide (\( \text{Al}_4\text{C}_3 \))
- Heavy Water (\( \text{D}_2\text{O} \))

### Step 2: Understand the Products
When Aluminum Carbide reacts with Heavy Water, it produces:
- Aluminum Deteroxide (\( \text{AlOD}_3 \))
- Deterium Methane (\( \text{CD}_4 \))

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction can be written as follows:
\[ \text{Al}_4\text{C}_3 + 6 \text{D}_2\text{O} \rightarrow 4 \text{AlOD}_3 + 3 \text{CD}_4 \]

### Step 4: Analyze the Reaction
In this reaction:
- Each molecule of Aluminum Carbide reacts with Heavy Water to produce Aluminum Deteroxide and Deterium Methane.
- The Aluminum in Aluminum Carbide forms Aluminum Deteroxide, while the Carbon reacts with Deterium from Heavy Water to form Deterium Methane.

### Conclusion
Thus, when \( \text{Al}_4\text{C}_3 \) reacts with \( \text{D}_2\text{O} \), it produces Aluminum Deteroxide and Deterium Methane.

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