What happens when LiH reacts with `Al_2C_(16)?`

Answer

To solve the question of what happens when lithium hydride (LiH) reacts with aluminum chloride (Al2Cl6), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are lithium hydride (LiH) and aluminum chloride (Al2Cl6).

### Step 2: Understand the Nature of Al2Cl6
Aluminum chloride (Al2Cl6) is a dimer of aluminum chloride (AlCl3). This means that Al2Cl6 can be thought of as two AlCl3 units combined.

### Step 3: Write the Chemical Reaction
When lithium hydride reacts with aluminum chloride, it forms lithium aluminum hydride (LiAlH4) and lithium chloride (LiCl). The unbalanced reaction can be written as:
\[ \text{LiH} + \text{Al}_2\text{Cl}_6 \rightarrow \text{LiAlH}_4 + \text{LiCl} \]

### Step 4: Balance the Chemical Equation
To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is:
\[ 3 \text{LiH} + \text{Al}_2\text{Cl}_6 \rightarrow 2 \text{LiAlH}_4 + 6 \text{LiCl} \]

### Step 5: Identify the Products
The products of the reaction are lithium aluminum hydride (LiAlH4) and lithium chloride (LiCl). Lithium aluminum hydride is known for its use as a reducing agent in various chemical reactions.

### Final Answer
When lithium hydride (LiH) reacts with aluminum chloride (Al2Cl6), it produces lithium aluminum hydride (LiAlH4) and lithium chloride (LiCl).

---