Home
Class 11
CHEMISTRY
2g of Al is treated separately with exce...

2g of Al is treated separately with excess dilute `H_2SO_4` and excess NaOH. The ratio of volumes of Hydrogen evolved under similar condition is x y. Find `x/y`

Text Solution

Verified by Experts

`2Al+3H_(2)SO_(4) to Al_(2)(SO_(4))_(3)+3H_(2)`
`2Al+2NaOH+2H_(2) 2NaAlO_(2)+3H_(2)`
Ratio is 1:1
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    CBSE COMPLEMENTARY MATERIAL|Exercise Unit Test|11 Videos

  • HYDROGEN

    CBSE COMPLEMENTARY MATERIAL|Exercise 5 Mark Questions|15 Videos

  • HYDROCARBONS

    CBSE COMPLEMENTARY MATERIAL|Exercise UNIT TEST|16 Videos

  • ORGANIC CHEMISTRY: SOME BASIC PRINCIPLES AND TECHNIQUES

    CBSE COMPLEMENTARY MATERIAL|Exercise Unit test|16 Videos

Similar Questions

Explore conceptually related problems

2g of aluminium is treated, separately with excess of dilute H_(2)SO_(4) , and excess of NaOH , the ratio of volumes of hydrogen evolved is

When same amount of zinc is treated separately with excess of H_(2)SO_(4) and NaOH , the ratio of volumes of H_(2) evolved is:

When the same amount of zinc is treated separately with excess of H_(2)SO_(4) and excess of NaOH , the ratio of volumes of H_(2) evolved is:

When the same amount of Zn is treated with excess of H_(2)SO_(4) and excess of NaOH separately, the ratio of the volume of hydrogen evolved is-

When the same amount of zinc is treated separately with excess of sulphric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is