ethanol and methoxymethane are position isomers. State true or false

Answer

To determine whether the statement "ethanol and methoxymethane are position isomers" is true or false, we need to analyze the structures and functional groups of both compounds.

### Step-by-Step Solution:

1. **Identify the Structures**:
- Ethanol has the chemical formula \( \text{C}_2\text{H}_6\text{O} \) and its structure is \( \text{CH}_3\text{CH}_2\text{OH} \).
- Methoxymethane (also known as dimethyl ether) has the chemical formula \( \text{C}_2\text{H}_6\text{O} \) and its structure is \( \text{CH}_3\text{OCH}_3 \).

2. **Identify the Functional Groups**:
- In ethanol, the functional group is the hydroxyl group (-OH), which classifies it as an alcohol.
- In methoxymethane, the functional group is an ether, characterized by the presence of an oxygen atom between two carbon groups (R-O-R').

3. **Define Position Isomers**:
- Position isomers are compounds that have the same molecular formula and functional group, but differ in the position of the functional group within the molecule.

4. **Define Functional Group Isomers**:
- Functional group isomers are compounds that have the same molecular formula but differ in the type of functional group present.

5. **Comparison**:
- Ethanol and methoxymethane have the same molecular formula \( \text{C}_2\text{H}_6\text{O} \) but differ in their functional groups (alcohol vs. ether).
- Since they do not have the same functional group, they cannot be position isomers.

6. **Conclusion**:
- Therefore, the statement "ethanol and methoxymethane are position isomers" is **false**. They are actually functional group isomers.

### Final Answer:
**False**: Ethanol and methoxymethane are not position isomers; they are functional group isomers.