Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g `mol^(-1)`) in 250 g of water . (`K_(f)` of water = `1.86 K kg mol^(-1)`)

Explanation

`Delta T_f=k_tm`
`=k_f (w_2 times 1000)/(M_2 times w_1)`
`=(1.86 times 60 times 1000)/(180 times 250)`
`=2.48K`
`Delta T_f= T_f^@=T_f`
`2.48=273.15-T_f`
`T_f=270.67K//270.52K//-2.48^@C`