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The vapour pressure of water is 12.3 Kpa...

The vapour pressure of water is 12.3 Kpa at 300K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.

Text Solution

Verified by Experts

Mole fraction of solute = `(1)/(1 + (1000)/(18)) = 0.0177`
`(P^(0) - P_(A))/(P^(0)) = 0.0177`
`(12.3 - P_(A))/(12.3) = 0.0177`
`P_(A) = 12.08 ` Kpa
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