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An anti-freeze solution is prepared from...

An anti-freeze solution is prepared from 222.6 g of ethylene glycol `C_(2) H_(4) (OH)_(2)` and 200 g of water . Calculate the molality of the solution. If the density of this solution be `1.072 g mL^(-1)` , what will be the molarity of the solution ?

Text Solution

Verified by Experts

Mg of `C_(2) H_(4) (OH)_(2) = 62 g mol^(-1)`
Molality = `(n_(B))/(W_(A)) xx 1000 = (W_(B))/(M_(B) xx W_(B)) xx 1000 = (222.6 xx 1000)/(62 xx 200) = 17.95 m `
Density = `("Mass")/("Volume")`
So , Volume = `("Mass")/("Density") = (422.6)/(1.072) = 394.22` ml
`M = (n_(B))/(V) xx 1000`
`= (222.6)/(394.22 xx 62) xx 1000 = 9.11` M
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