Home
Class 12
CHEMISTRY
A + 2Bto 3C + 2D The rate of disappe...

A + 2B`to` 3C + 2D
The rate of disappearance of B is `1xx 10^(–2) "mol L"^(–1) "sec"^(–1)`. What will be (i) rate of reaction (ii) rate of change in the concentration of A and C ?

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the given reaction and the rate of disappearance of reactant B. The reaction is as follows: \[ A + 2B \rightarrow 3C + 2D \] Given: - The rate of disappearance of B, \( \frac{-d[B]}{dt} = 1 \times 10^{-2} \, \text{mol L}^{-1} \text{s}^{-1} \) ### Step 1: Determine the Rate of Reaction ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    CBSE COMPLEMENTARY MATERIAL|Exercise SHORT ANSWER TYPE-II QUESTIONS|23 Videos

  • BIOMOLECULES

    CBSE COMPLEMENTARY MATERIAL|Exercise SHORT ANSWER-II TYPE QUESTION|13 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTIONS|2 Videos

Similar Questions

Explore conceptually related problems

In the reaction A+2B to 3C + 2D , the rate of disappearance of B is 1 xx 10^(-2) mol L^(-1)s^(-1) . What will be the rate of the reaction and rate of change in concentration of A and C?

(a) Define the following : (i) Order of reaction (ii) Activation energy of reaction (b) A+2Brarr3C+2D . The ratio of disapppearance of B is 1xx10^(-2) molL^(-1)s^(-1) . What will be (i) Rate of the reaction (ii) Rate of change in concentration of A and C?

For a reaction , 2A+D rarr3C , the rate of appearance of C at time t is 1.2 xx10^(-4) "mol L"^(-1) s^(-1) . Find the rate of reaction.

For an elementary, 2A+Bto3C , the rate of appearance of C at time 't' is 1*3xx10^(-4)"mol "L^(-1)s^(-1) . Calculate at this time (i) rate of the reaction (ii) rate of disappearance of A.

For the elementary reaction 2A + B to 3C , if the rate of appearance of C at time 't' is 1.3 xx 10^(-4)mol L^(-1)s^(-1) , calculate at this time (i) rate of the reaction (ii) rate of disappearance of A.

The order of a reaction having rate constant 1.34xx10^(-3) "mol" L^(-1) "sec"^(-1) will be :