A compound `A` having molecular formula `C_(3)H_(7)ON` reacts with `Br_(2)` in presence of `NaOH` to give compound 'B'. This compound 'B' reacts with `HNO_(2)` to form alcohol and `N_(2)` gas. Identify compound 'A' and 'B' and write the reaction involved.

Explanation

To solve the problem, we will identify compounds A and B based on the given reactions and their characteristics.

### Step 1: Identify Compound A
The molecular formula of compound A is given as \( C_3H_7ON \). This suggests that compound A is an amide because it reacts with \( Br_2 \) in the presence of \( NaOH \) to form compound B.

Given the formula, we can deduce that compound A is likely to be propanamide, which has the structure:
\[
\text{CH}_3\text{CH}_2\text{C(=O)NH}_2
...