A dihybrid heterozygous round, yellow seeded garden pea (Pisum sativum) was crossed with a double reccessive plant. Work out the genotype and phenotyepe of the progeny.
Text Solution
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To solve the problem of determining the genotype and phenotype of the progeny from a dihybrid heterozygous round, yellow-seeded garden pea crossed with a double recessive plant, we can follow these steps:
### Step 1: Identify the Genotypes of the Parents
- The dihybrid heterozygous plant has the genotype: **RrYy** (where R = round seed, r = wrinkled seed, Y = yellow seed, y = green seed).
- The double recessive plant has the genotype: **rryy**.
### Step 2: Determine the Gametes Produced by Each Parent
- The heterozygous plant (RrYy) can produce four types of gametes due to independent assortment:
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CBSE COMPLEMENTARY MATERIAL-PRINCIPLES OF INHERITANCE AND VARIATION-QUESTIONS (LA)
