A dihybrid heterozygous round, yellow seeded garden pea (Pisum sativum) was crossed with a double reccessive plant.What principle of Mendel is illustrated through the result of this cross ?
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To solve the question regarding the cross of a dihybrid heterozygous round, yellow seeded garden pea (Pisum sativum) with a double recessive plant, we can follow these steps:
### Step 1: Identify the Genotypes
The dihybrid heterozygous plant has the genotype:
- Round seeds (R) are dominant over wrinkled seeds (r)
- Yellow seeds (Y) are dominant over green seeds (y)
Thus, the genotype of the heterozygous plant is:
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A heterozygous round seeded (Rr) plant is crossed to recessive wrinkled (rr) seeded plant. The progeny would be:
A double homozygous yellow round seeded plant of Pea is crossed with green wrinkled seeded plant. The offspring shall be of
A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the F_(1) plant were selfed the resulting genotypeswere in the ratio of
A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. Whan the F_(1) plants were selfed the resulting genotypes were in the ratio of :
A heterozygous round and yellow seeded pea plant was crossed with wrinkled and green seeded pea plant. Considering that the genes for seed shape and seed colour are completely linked, calculate the percentage of plants with round and green seeds
A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the F_(1) plants were selfed the resulting genotypes were in the ratio of
CBSE COMPLEMENTARY MATERIAL-PRINCIPLES OF INHERITANCE AND VARIATION-QUESTIONS (LA)
